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The ratio of half life and two third life (t2/3) for a second order kinetics is


     1. 3 : 4

     2. 2 : 3

     3. 3 : 2

     4. 1 : 2
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ans - 4

I want explanation[/hide]

For a second order reaction,


dA/dt = - k A[p]2[/p]

This implies

-dA/A[p]2[/p]=k dt

Integrating, we get


1/A-1/A[ss]f[/ss]=k t


1/A-1/(A/2) = k t[ss]1/2[/ss]
-1/A = k t[ss]1/2[/ss]

so


1/A-1/(2A/3) = k t[ss]1/2[/ss]
-1/2A = k t[ss]2/3[/ss]


From which you get option 4

" 1/A-1/(2A/3) = k t1/2  " --->  Sir here u mean t 2/3 ??

If yes then ya I got ur method

THANKS