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#1 Posted 8:24pm 08-02-10 Capilarity[image]41140706.jpg[/image] I need ans to Q2,3 only |
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#2 Posted 11:10pm 08-02-10 Re: Capilarityok..let me make things easy for everyone...point out mistake in soln for 2 [image]41150720.jpg[/image] |
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#3 Posted 00:28am 09-02-10 Re: Capilarity@ eure ,when u insert capillary in the lower liquid according to ur solution there will b only denser liq. in the capillary.but in fact in the begining when u insert the capillary in the lower liquid u hav to pass it through upper one.hence the upper liquid will first enter into it .again when their will b capillary rise or fall there iz no chance of this liquid to com out of capillary. so u hav to solve as below [b]las we dont know wheather the liquid will rise or fall let it b rises to an height h ,then P[ss]0[/ss]-2T/r-[u]hρ*g-H/2.ρ/2.g[/u]=P[ss]0[/ss]-H/2. ρ/2.g =>h=-2T/r [/b] plz cheak the answer.if wrong then verify my process also.
swaraj ha ha ha Edited on 4:54pm 15-02-10 |
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#4 Posted 1:58pm 15-02-10 Re: Capilarityans is 4T/r |
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#5 Posted 4:55pm 15-02-10 Re: Capilarityplz verify my ressult and find out the mistake
swaraj ha ha ha |
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#6 Posted 9:52pm 15-02-10 Re: Capilarityindeed it will be 4T/r,coz, since the topmost liquid is in the upper part and so the only upward force given is by the topmost liquid's surface tension which can balance only a column of liquid whch it supported originally when contact was not made with the denser liquid thus the answer,,,,,
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#7 Posted 10:32pm 15-02-10 Re: Capilaritypoint out my mistake... |
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#8 Posted 07:05am 16-02-10 Re: Capilarityurgh..........u forgot the surface tension.........in your FBD...........
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#9 Posted 08:21am 16-02-10 Re: Capilarityexcess pressure comes from surface tension...... i wrote that part naa.... |
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#10 Posted 11:27pm 09-03-10 Re: Capilarity????????? |
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#11 Posted 08:10am 26-03-10 Re: Capilarityno one ?? |
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#12 Posted 09:07am 26-03-10 Re: CapilarityThe pressure difference between the "inside" and "outside" of a curved meniscus is Δp = [frac]2S[/]R[/frac] with S being the surface tension and R the radius of the curved surface. ii) Suppose the liquid rises to a height h above the upper surface of lighter liquid. Then just inside the meniscus the pressure p is obtained by the relation [im]http://codecogs.izyba.com/gif.latex?p_0-p%20%3D%20%5Cdfrac%7B2S%5Ccos%5Ctheta%7D%7Br%7D[/im] r being the radius of the capillary tube and θ the contact angle. Balancing pressure at the bottom of the capillary tube, we get [im]http://codecogs.izyba.com/gif.latex?p+%5Cdfrac%7B%5Crho%7D%7B2%7D%5C%2Cg%28h+H%29+%5Crho%20gx%20%3D%20p_0+%5Cdfrac%7B%5Crho%7D%7B2%7D%5C%2CgH+%5Crho%20gx[/im] where x is the distance by which the capillary tube has been dipped in the lower liquid (having higher density). From the above two relations we obtain, [im]http://codecogs.izyba.com/gif.latex?%5Cdfrac%7B%5Crho%7D%7B2%7D%5C%2Cgh%20%3D%20p_0-p%3D%5Cdfrac%7B2S%5Ccos%5Ctheta%7D%7Br%7D[/im] giving [im]http://codecogs.izyba.com/gif.latex?%5Cboxed%7Bh%20%3D%5Cdfrac%7B4S%5Ccos%5Ctheta%7D%7B%5Crho%20gr%7D%7D[/im] |
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