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#1 Posted 08:22am 29-01-10 alg dbts1)If a>0>b>c & the system of eqn ax+by+cz,bx+cy+az=0,cx+ay+bz=0 has a non trivial soln,then find nature of roots of (b+c)t[p]2[/p]+(c+a)t+a+b=0 . From first 3 eqns i got a+b+c=0 what next ?? 2) Let (1+x)[p]2n[/p]=a[ss]0[/ss]+a[ss]1[/ss]x+....+a[ss]2n[/ss]x[p]2n[/p] A:a[ss]0[/ss]+a[ss]2[/ss]+a[ss]4[/ss]....+a[ss]2n[/ss]=1/2 (a[ss]0[/ss]+a[ss]1[/ss]+a[ss]2[/ss]....+a[ss]2n[/ss]) R:a[ss]n+1[/ss]<a[ss]n[/ss] & a[ss]n-3[/ss]=a[ss]n+3[/ss] which option do u guys support ?? a/b
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#2 Posted 09:50am 29-01-10 Re: alg dbtsWell if you have got a+b+c=0, then t=1 is a root. |
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#3 Posted 09:54am 29-01-10 Re: alg dbtsQ2. I would say (c)
sadly life is not masti in IITK with MTH 101 making first yr hell fr all freshers (no exception)... even got seniors repeating the course |
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#4 Posted 4:27pm 29-01-10 Re: alg dbtsthanks sir @asish how ??
http://mymundus.blogspot.com/ |
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#5 Posted 07:14am 30-01-10 Re: alg dbts2) the exapansion has 2n+1 terms and a[ss]n+1[/ss] being the greatest . thus R is false .
God made the laws only nearly symmetrical so that we should not be jealous of His perfection!- Feynman |
