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#1 Posted 9:30pm 16-03-10 doubt in opticsA diverging lens is placed at origin of coordinate sysytem.eqn of incident ray is y=-x/2+3. The focal length of lens is 4 cm. find eqn of divergent ray... please help....anyone..[image]44255093.jpg[/image]
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#2 Posted 11:20pm 16-03-10 Re: doubt in opticsThis question has been dicussed earlier here... http://www.targetiit.com/iit-jee-forum/posts/a-question-on-convex-lens-14509.html |
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#3 Posted 1:31pm 17-03-10 Re: doubt in opticscan anyone give a detailed solution...
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#4 Posted 3:23pm 18-03-10 re-doubt in optics???..
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#5 Posted 10:39pm 18-03-10 Reits y-3=x/4. u=6 (ray wud hv intersected x-axis there) so, v=-12 2 pts for the refracted ray are (-12,0) & (0,3) |
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#6 Posted 4:14pm 19-03-10 retthough d ans is correct...i didnt get d u=6 part...isnt d ray coming from infinity......
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#7 Posted 10:52am 20-03-10 Re: doubt in optics@smriti....how did u get that eqn ?? |
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