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#1 Posted 1:25pm 28-02-10  

EM

an emf of  V = 150 cos 377t is applied to a pure resistor of resistance  50 Ω .

what is frequency of power variation  
   

Manmay

#2 Posted 1:48pm 28-02-10  

Re: EM

P = V[p]2[/p]/R

P = [frac](150)[p]2[/p]cos [p]2[/p] 377t [/]50[/frac]

P = 450 cos [p]2[/p] 377t

P = 450( 1 + cos 2. 377t)

P = 450 + 450cos 754t

compare 450cos 754t with A cos wt

we get w = 754 = 2pi/T.

1/T = 754/2pi = 120 Hz.
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