|
#1 Posted 1:48pm 12-01-10 even/odd[image]38784214.jpg[/image]
coming soon! |
|
#2 Posted 1:48pm 12-01-10 Re: even/oddi m getting c
coming soon! |
|
#3 Posted 1:53pm 12-01-10 Re: even/oddremember that [y] + [-y] = -1 when y is not an integer. |
|
#4 Posted 2:23pm 12-01-10 Re: even/oddsir, i asked coz in book ans. given is (b)...........so wat is correct ans?????? [hide]i m getting it as neither odd nor even[/hide]
coming soon! |
|
#5 Posted 2:24pm 12-01-10 Re: even/oddi was trying to lead you to proving that its an odd function |
|
#6 Posted 2:27pm 12-01-10 Re: even/oddi tried using f(x)+f(-x)=0 to check if its odd...........but concluded that it is not odd.........maybe i m doing some error .....plz provide ur solution thnx
coming soon! |
|
#7 Posted 3:41pm 12-01-10 Re: even/odd??
coming soon! |
|
#8 Posted 8:19pm 12-01-10 Re: even/oddcos(-x)=cosx ... so lets conc only on Denominator g(x)=[[frac]2x[/]π[/frac]]+[frac]1[/]2[/frac] g(-x)=[[frac]-2x[/]π[/frac]]+[frac]1[/]2[/frac] =-[[frac]2x[/]π[/frac]]-1+[frac]1[/]2[/frac] =-[[frac]2x[/]π[/frac]]-[frac]1[/]2[/frac] =-([[frac]2x[/]π[/frac]]+[frac]1[/]2[/frac]) clearly g(x) is odd => f(x) is odd
It is better to be defeated on principle than to win on lies
|
