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#1 Posted 11:40pm 29-01-10 hilarious doubts of ATGS...x[p]2[/p]+y[p]2[/p]=1....is a circle.. so, y[p]2[/p]=1-x[p]2[/p]...is a circle.. implies.., y=±[sqrt]1-x[p]2[/p][/sqrt]... so what is the graph of y=±[sqrt]1-x[p]2[/p][/sqrt](sin x) please help...also point out wether or not the doubt makes any sense...
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#2 Posted 00:11am 30-01-10 RE: hilarious doubts of ATGS...arre koi toh answer karo!!
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#3 Posted 10:41am 30-01-10 Re: hilarious doubts of ATGS...actually wat i think is pattern of the graph will be quiet similar to graph of [b]x. sin x[/b] for y=+√1-x[p]2[/p]sinx and [b]-x. sin x[/b] for y=-√1-x[p]2[/p] sinx 
Edited on 0:56pm 30-01-10 |
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#4 Posted 0:43pm 30-01-10 Re: hilarious doubts of ATGS...yup...then explain y x[p]2[/p]+y[p]2[/p]=1 is a circle??
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#5 Posted 0:49pm 30-01-10 Re: hilarious doubts of ATGS...wat!? [im]http://www.mathlinks.ro/images/smiles/ohmy.gif[/im] wer r u contradicting that x[p]2[/p]+y[p]2[/p]=1 is not a circle! din get ur point
Edited on 0:50pm 30-01-10 |
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#6 Posted 1:56pm 30-01-10 Re: hilarious doubts of ATGS...x[p]2[/p]+y[p]2[/p]=1 implies, y=±[sqrt]1-x[p]2[/p][/sqrt] whch r two st lines... so y is the function a circle???
"Every physicist thinks that he knows what a photon is...I spent my life to find out what a photon is and I still don't know it!!!"- _Einstein_ |
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#7 Posted 2:02pm 30-01-10 Re: hilarious doubts of ATGS...array how r dey two str lines ?? infact y=√(1-x[p]2[/p]) is equation of semi circle
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#8 Posted 10:52pm 04-02-10 Re: hilarious doubts of ATGS...@ subhomoy i dont think x[p]2[/p]+y[p]2[/p]=1 represent a function itz a relation.....so y=[sqrt]1-x[p]2[/p][/sqrt] is not a function of st line at all
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