Guest
Displaying Posts 1 - 3 of 3|
#1 Posted 1:35pm 22-01-10 inequality1.find min value of:secA+secB+secC where A+B+C=PI. |
|
#2 Posted 2:09pm 22-01-10 Re: inequalitydo you need A,B,C to be acute angles of a triangle? |
|
#3 Posted 2:14pm 22-01-10 Re: inequalityASSUMING ANGLES ARE ACUTE consider the graph of secx in x →(0,π/2) now consider points x_1 ,x_2 ,x_3 such that x_1 + x_2 +x_3 = π now a triangle will be formed using f(x_1),f(x_2)and f(x_3) the y-cordinate centroid of this triangle will be always lying above f(x_1 +x_2 +x_3 /3) i.e f(x- cordinate of centroid) hence we get the inequality secA+secB+secC /3 ≥ sec(pi/3) secA+secB+secC ≥6 [im]http://targetiit.com/images/forum/39650068.jpg[/im]
Edited on 2:21pm 22-01-10 |
Displaying Posts 1 - 3 of 3
