TargetIIT

[im]http://alt2.mathlinks.ro/latexrender/pictures/d/a/4/da45c6e4fbb7183d3f446176dc652673258b59b5.gif[/im]

how u solve it ?

is it
aritmetic mean of a[ss]i[/ss] ?

well arithmetic mean of a[ss]i[/ss] is wen m was not varying

here m is also tending to infinity

btw i dunno the ans

0 is the ans!

[im]http://codecogs.izyba.com/gif.latex?\text{SOLUTION%20:%20}%20\\%20n\left(\sqrt[m]{\left(%201+\frac{a_1}{n}\right)\left(%201+\frac{a_2}{n}\right)\left(%201+\frac{a_3}{n}\right)\left(%201+\frac{a_4}{n}\right)........\left(%201+\frac{a_m}{n}\right)}%20-1\right)\\%20n\left(%20\left(1+\left(%20\frac{\sum{a_i}}{n}%20+...........\right)\right)^{\frac{1}{m}}-1\right)%20\\%20n\left(\left(%20\frac{\sum{a_i}}{mn}+.......)%20\right+%20higher%20\%20powers%20\right)%20\right)%20\\%20\text{the%20constant%20terms%20comes%20out%20to%20be%20}\frac{\sum{a_i}}{m}=arithmetic%20\%20mean%20\\%20\lim_{m\rightarrow%20\infty}%20\frac{\sum{a_i}}{m}%20=0[/im]

@akari how u got ur last step ?

Σa[ss]i[/ss] is not constant its tending to ∞

so u cant hav lim as 0