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#1 Posted 1:26pm 05-03-10 MORE THAN 1 RIGHT - ROLLING!a solid cylinder of mass M is rolled horizontally on a rough surface with a force F acting on centre of mass (actually there is a diag but has just a cylinder horizontally rolling and F is acting towards right from centre.Then a) accn of COM is [frac]F/M[/frac] b)accn of COM is [frac]F[/]2M[/frac] c) the force of friction acts backward on the cylinder d) magnitude of force of friction is [frac]F[/]3[/frac] [hide]note F acts towards right>[/hide]
Edited on 2:19pm 05-03-10 |
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#2 Posted 1:38pm 05-03-10 Re: MORE THAN 1 RIGHT - ROLLING!??????????? |
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#3 Posted 2:20pm 05-03-10 Re: MORE THAN 1 RIGHT - ROLLING!plzzz |
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#4 Posted 2:39pm 05-03-10 Re: MORE THAN 1 RIGHT - ROLLING!ans: c and d.
Don't concentrate on the finger............or you'll miss all the Heavenly Glory ( Enter the Dragon) |
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#5 Posted 5:25pm 05-03-10 Re: MORE THAN 1 RIGHT - ROLLING!The answer shud be C and D let f[ss]r[/ss] be the frictional force.. draw the fbd and u will notice that f[ss]r[/ss] is acting backwards.. F - f[ss]r[/ss] = Ma balancing of forces f[ss]r[/ss].R = MR[p]2[/p]α/ 2 torque eq[p]n[/p] f[ss]r[/ss] = Ma/2 since pure rolling so a = Rα F = 3Ma/2 acceleration of centre of mass = 2F/3M |
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