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#1 Posted 0:37pm 12-03-10 Objective IV2. [sqrt]1-x[p]2[/p][/sqrt] + [sqrt]1-y[p]2[/p][/sqrt] = a(x-y) then dy/dx is a) (1-x[p]2[/p])/(1-y[p]2[/p]) b) (1-y[p]2[/p])/ (1-x[p]2[/p]) c) ([sqrt]1-x[p]2[/p])/(1-y[p]2[/p][/sqrt]) d) [sqrt]1-y[p]2[/p])/ (1-x[p]2[/p])[/sqrt]
Edited on 3:16pm 12-03-10 |
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#2 Posted 0:53pm 12-03-10 Re: Objective IVAns 4...- [sqrt]a[p]2[/p] + b[p]2[/p][/sqrt] < asinx + bcosx < [sqrt]a[p]2[/p] + b[p]2[/p][/sqrt].. so answer is [sqrt]2[/sqrt]. Ans 5...d Ans 3..d...use -dx/dy for finding the normal..and point is in first quadrant..
Edited on 2:55pm 12-03-10 |
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#3 Posted 1:01pm 12-03-10 Re: Objective IV1.a --8a[p]2[/p]/3 [image]43879101.jpg[/image] [/im][im]http://codecogs.izyba.com/gif.latex?%5Cint_%7B0%7D%5E%7Ba%7D%7B%5Csqrt%7B4ax%7D%20dx%7D%3D%5B4/3%5Csqrt%7Ba%7Dx%5E%7B3/2%7D%5D_%7B0%7D%5Ea%3D8/3a%5E2[/im]
bye tiit Edited on 1:06pm 12-03-10 |
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#4 Posted 1:05pm 12-03-10 Re: Objective IVfor 2nd one put [im]http://codecogs.izyba.com/gif.latex?x%20%3D%20sin%20%5Calpha[/im] and [im]http://codecogs.izyba.com/gif.latex?y%20%3D%20sin%20%5Cbeta[/im]
Edited on 1:05pm 12-03-10 |
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