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#1 Posted 10:09pm 10-03-10 Principle Of suerpositionCan anyone plzz explain the principal of superposition in electrical circuits I have learnt it before from Arihant But had some conceptual doubts Hence this thread
But there is suffering in life, and there are defeats. No one can avoid them. But it's better to lose some of the battles in the struggles for your dreams than to be defeated without ever knowing what you're fighting for.
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#2 Posted 10:14pm 10-03-10 Re: Principle Of suerpositionAbt the principle of superposition....it is helpful in finding the net resistance of some complicated circuits which have axis of symmetry..just fold the circuit abt that axis and the two symmetric resistances will be in parallel.... |
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#3 Posted 10:21pm 10-03-10 Re: Principle Of suerpositionIt simply says that the voltage soruces act as if the others were not present. So you can solve the circuit neglecting the other emf sources and finally adding the individual effect of all the emf sources individually..
-when spring comes, it melts the snow one flake at a time… Edited on 10:21pm 10-03-10 |
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#4 Posted 10:26pm 10-03-10 Re: Principle Of suerposition[image]43740145.jpg[/image] CAN U SOLVE THIS BASED ON THE PRINCIPLE PLZZ???? [hide]RESISTORS LOOK MORE LIKE WORMS DONT MIND[/hide] [3]
But there is suffering in life, and there are defeats. No one can avoid them. But it's better to lose some of the battles in the struggles for your dreams than to be defeated without ever knowing what you're fighting for.
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#5 Posted 11:04pm 10-03-10 Re: Principle Of suerpositionYes - first consider the circuit with the 10.3V battery, and the other one is absent. Figure out the current in the individual branches. Now repeat the same thing with the other battery, finally add up the individual currents in each branch. Could not provide numerical soln, due to respect for some fantastic art-work. [26] |
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#6 Posted 00:26am 11-03-10 Re: Principle Of suerpositionFirstt look at the 10.8 V battery only Lets say that we are interestedin the current through the 12 ohm resistor.. So we will remove the 14.4 V SO we have a parallel between 12 and 8 whcih will effectively be 12.8/(12+8) = 96/20 = 4.8 ohm.. That along with 4+2+4.8=10.8 ohm THe current due to this is 10.8/10.8=1 in the main wire and 8/20 ampere in the wire through the 12 ohm resisitor Again repeat the same for 14.4 (we remove the 10.8 ohm resistor) We have (4+2) and 12 in parallel.. effective reisistance = 12x6/18 = 4 ohm In series with another 8 which is 12 ohm.. 14.4/12=1.2 of which, (4+2)/18 x 1.2 = 0.4 amp goes in the 12 ohm resistance Also the direction of current is opposite due to both .. so the net current will be 1-.4=.6 amp.
-when spring comes, it melts the snow one flake at a time… |
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#7 Posted 9:48pm 11-03-10 Re: Principle Of suerpositionThaNks Nishant Sir , Soumik & Govind @Nishant Sir thanks for the solution of the prob I've got a clear idea now [1]
But there is suffering in life, and there are defeats. No one can avoid them. But it's better to lose some of the battles in the struggles for your dreams than to be defeated without ever knowing what you're fighting for.
Edited on 9:48pm 11-03-10 |
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